Решение:
set nocount on declare @name varchar(128), @substr nvarchar(4000), @column varchar(128) set @substr = '%Всесезонка%' --фрагмент строки, который будем искать create table #rslt (table_name varchar(128), field_name varchar(128), value ntext) declare s cursor for select table_name as table_name from information_schema.tables where table_type = 'BASE TABLE' order by table_name open s fetch next from s into @name while @@fetch_status = 0 begin declare c cursor for select quotename(column_name) as column_name from information_schema.columns where data_type in ('text', 'ntext', 'varchar', 'char', 'nvarchar', 'char', 'sysname') and table_name = @name set @name = quotename(@name) open c fetch next from c into @column while @@fetch_status = 0 begin print 'Processing table - ' + @name + ', column - ' + @column exec('insert into #rslt select ''' + @name + ''' as Table_name, ''' + @column + ''', ' + @column + ' from' + @name + ' where ' + @column + ' like ''' + @substr + '''') fetch next from c into @column end close c deallocate c fetch next from s into @name end select table_name as [Table Name], field_name as [Field Name], count(*) as [Found Mathes] from #rslt group by table_name, field_name order by table_name, field_name --Если нужно, можем отобразить все найденные значения select * from #rslt order by table_name, field_name drop table #rslt close s deallocate s